Question

What is an equation in point-slope form of the line that passes through (1, -6) and (4, 6)?

Answer 1

Answer:

$y+6=4(x-1)$ or $y-6=4(x-4)$

Step-by-step explanation:

We want to find the equation in point-slope form of the line that passes through the two points (1, -6) and (4, 6).

Recall that point-slope form is given by:

$y-y_{1}=m(x-x_{1})$

Where m is the slope.

Find the slope m using the two given points.

$\displaystyle m = \frac{\Delta y}{\Delta x} = \frac{6-(-6)}{4-1} = \frac{12}{3} = 4$

Substitute. We can use either point. Using the point (1, -6), we acquire:

$y-(-6)=4(x-(1))$

Simplify:

$y+6=4(x-1)$

And using the point (4, 6), we acquire:

$y-(6)=4(x-(4))$

Simplify:

$y-6=4(x-4)$