Respuesta :
Question Completion
(b) Use the possibility diagram to calculate the probability that the product of the two numbers is
I) A prime number
ii) Not a perfect square
iii) A multiple of 5
iv) Less than or equal to 21
v) Divisible by 4 or 6
Answer:
I) 0.125 (ii)0.828125 (iii)0.234375 (iv) 0.625 (v)0.65625
Step-by-step explanation:
The sample space for an 8-sided fair die rolled twice is:
[tex][(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6),(1, 7),(1, 8)\\(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6),(2, 7),(2, 8)\\(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6),(3, 7),(3, 8)\\(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6),(4, 7),(4, 8)\\(5, 1), (5, 2), (5, 3), (5, 4), (5, 5),(5, 6),(5, 7),(5, 8)\\(6, 1), (6, 2), (6, 3), (6, 4)(6, 5),(6, 6),(6, 7),(6, 8)\\(7, 1), (7, 2), (7, 3), (7, 4)(7, 5),(7, 6),(7, 7),(7, 8)\\(8, 1), (8, 2), (8, 3), (8, 4)(8, 5),(8, 6),(8, 7),(8, 8)]\\[/tex]
(a) The possibility diagram of the product of the two numbers appearing on the die in each throw
[tex]1, 2, 3, 4, 5, 6,7,8\\2, 4, 6, 8, 10, 12,14,16\\3,6,9,12,15,18,21,24\\4,8,12,16,20,24,28,32\\5,10,15,20,25,30,35,40\\6,12,18,24,30,36,42,48\\7,14,21,28,35,42,49,56\\8,16,24,32,40,48,56,64[/tex]
(b)
I) A prime number
The number of products that gives prime numbers = 8
[tex]P$(Product is a prime number)=\dfrac{8}{64}= \dfrac{1}{8}\\=0.125[/tex]
ii) Not a perfect square
Number of products which results in perfect squares =11
[tex]P$(Product is Not a perfect square)=\dfrac{64-11}{64}= \dfrac{53}{64}\\=0.828125[/tex]
iii) A multiple of 5
Number of products that are multiples of 5=15
[tex]P$(product is a multiple of 5)=\dfrac{15}{64}\\=0.234375[/tex]
iv) Less than or equal to 21
Number of products which are less than or equal to 21=40
[tex]P$(product is less than or equal to 21)=\dfrac{40}{64}=\dfrac{5}{8}\\=0.625[/tex]
v) Divisible by 4 or 6
Products Divisible by 4 or 6= 42
[tex]P$(product is divisible by 4 or 6)=\dfrac{42}{64}=\dfrac{21}{32}\\=0.65625[/tex]
