Question

Solve the following equation algebraically:
4x2 = 100
a. +0.2
b. +5
C.
+12.5
+10
d.

Answer 1

Answer:

$\boxed{\sf \ \ \ answer \ b. \ \ +5 \ \ \ }$

Step-by-step explanation:

Hello

let's assume that we are looking for x >=0

$4x^2=100 <=> \dfrac{4x^2}{4}=x^2=\dfrac{100}{4}=25\\<=>\sqrt{x^2}=25\\<=> |x| = 5 <=> x = 5 \ or \ x=-5$

Let's assume that we are looking for x>=0

so the correct answer is 5