Question

What is K for (CH3)2N(aq) + H20() = (CH3)2NH(aq) + OH(aq)?
A. [(CH 3N][(CH NH*]
В. к.
[(CH3)3N]
[(CH3)2NH* [OH-]
C. Ko
[(CH, NH* ||CH"]
[(CHz),N]
D. K
[(CH, NH*]
[(CH2),N]​

Answer 1

Answer: $K=\frac{[OH^-]\times [(CH_3)2NH]}{[(CH_3)_2N]}$

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as $K$

For the given chemical reaction:

$(CH_3)_2N(aq)+H_2O(l)\rightarrow (CH_3)2NH(aq)+OH^-(aq)$

The concentration of pure solids and pure liquids is taken as 1.

Thus $K=\frac{[OH^-]\times [(CH_3)2NH]}{[(CH_3)_2N]}$