Respuesta :

Answer:

[tex]log_3(81) = 4[/tex]

Step-by-step explanation:

Given

[tex]3^4 = 81[/tex]

Required

Rewrite in logarithmic form

We start by taking log of both sides

[tex]3^4 = 81[/tex]

[tex]log3^4 = log81[/tex]

From laws of logarithm;

[tex]loga^b = b\log(a)[/tex]

So; [tex]log3^4 = log81[/tex] becomes

[tex]4log3 = log81[/tex]

Divide both sided by log3

[tex]\frac{4log3}{log3} = \frac{log81}{log3}[/tex]

[tex]4 = \frac{log81}{log3}[/tex]

From laws of logarithm;

[tex]\frac{loga}{logb} = log{_b}(a)[/tex]

So;

[tex]4 = \frac{log81}{log3}[/tex] becomes

[tex]4 = log_3(81)[/tex]

[tex]log_3(81) = 4[/tex]

Hence, [tex]3^4 = 81[/tex] in logarithm form is [tex]log_3(81) = 4[/tex]

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