Answer:
[tex]log_3(81) = 4[/tex]
Step-by-step explanation:
Given
[tex]3^4 = 81[/tex]
Required
Rewrite in logarithmic form
We start by taking log of both sides
[tex]3^4 = 81[/tex]
[tex]log3^4 = log81[/tex]
From laws of logarithm;
[tex]loga^b = b\log(a)[/tex]
So; [tex]log3^4 = log81[/tex] becomes
[tex]4log3 = log81[/tex]
Divide both sided by log3
[tex]\frac{4log3}{log3} = \frac{log81}{log3}[/tex]
[tex]4 = \frac{log81}{log3}[/tex]
From laws of logarithm;
[tex]\frac{loga}{logb} = log{_b}(a)[/tex]
So;
[tex]4 = \frac{log81}{log3}[/tex] becomes
[tex]4 = log_3(81)[/tex]
[tex]log_3(81) = 4[/tex]
Hence, [tex]3^4 = 81[/tex] in logarithm form is [tex]log_3(81) = 4[/tex]