Write an equation for the graph below, which represents an exponential function f with base 2 or 3, translated and/or reflected.

Answer:
[tex]f(x) = 2*2^x + 3[/tex]
Step-by-step explanation:
The model for an exponencial function is:
[tex]f(x) = a*b^x + c[/tex]
'c' is the value of the asymptote, so we have c = 3.
To find the value of 'a', let's use the point (0,5):
[tex]5 = a*b^0 + 3[/tex]
[tex]5 = a*1 + 3[/tex]
[tex]a = 2[/tex]
Now, to find the value of 'b', let's use the point (1, 7):
[tex]7 = 2 * b^1 + 3[/tex]
[tex]7 = 2b + 3[/tex]
[tex]2b = 4[/tex]
[tex]b = 2[/tex]
So our function is:
[tex]f(x) = 2*2^x + 3[/tex]
Let's check if the point (-1, 4) is inside our function:
[tex]4 = 2 * 2^{-1} + 3[/tex]
[tex]4 = 1 + 3[/tex]
[tex]4 = 4\ (correct)[/tex]