Question

What are the two solutions of 2x^2 = -x2 – 5x - 1?

Answer 1

Answer:

Step-by-step explanation:

Let's solve your equation step-by-step.

−$2x^2=-x^2-5x-1$1

Step 1: Subtract -x^2-5x-1 from both sides.

$2x^2-(-x^2-5x-1)=-x^2-5x-1-(x^2-5x-1)$

$3x^2+5x+1=0$

For this equation: a=3, b=5, c=1

$3x^2+5x+1=0$

Step 2: Use quadratic formula with a=3, b=5, c=1.

$x=\frac{-b+\sqrt{b^2-4ac} }{2a}$

$x=\frac{-(5)+\sqrt{(5)^2-4(3)(1)} }{2(3)}$

$x=\frac{-5+\sqrt{13} }{6}$

$x=\frac{-5}{6}+\frac{1}{6}\sqrt{13}$  or   $x=\frac{-5}{6}+\frac{-1}{6}\sqrt{13}$ This is the answer

I hope to help you :)