Answer:
The percentage of the drug in the mixture is 0.043%.
Explanation:
0.5 kg contains 0.038% of a drug.
Mass of the drug = 0.038% of 0.5
= [tex]\frac{0.038}{100}[/tex] × 0.5
= 0.00019
= 1.9 ×[tex]10^{-4}[/tex]
10 kg contains 0.043% of the same drug.
Mass of the drug = 0.043% of 10
= [tex]\frac{0.043}{100}[/tex] × 10
= 0.0043
= 4.3 × [tex]10^{-3}[/tex] kg
Total mass of drug = 0.00019 + 0.0043
= 0.00449
= 4.49 × [tex]10^{-3}[/tex] kg
Total mass of mixture = 0.5 kg + 10 kg
= 10.5 kg
Percentage of the drug in the mixture = [tex]\frac{4.49*10^{-3} }{10.5}[/tex] × 100
= 0.04276%
The percentage of the drug in the mixture is 0.043%.
