Help. Use two points on the line to find the equation of the line in,standard form

Answer:
3x - 4y = - 12
Step-by-step explanation:
The equation of a line in standard form is
Ax + By = C ( A is a positive integer and B, C are integers )
Calculate the equation in slope- intercept form
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]
with (x₁, y₁ ) = (- 4, 0) and (x₂, y₂ ) = (0, 3) ← 2 points on the line
m = [tex]\frac{3-0}{0+4}[/tex] = [tex]\frac{3}{4}[/tex]
The line crosses the y- axis at (0, 3) ⇒ c = 3
y = [tex]\frac{3}{4}[/tex] x + 3 ← in slope- intercept form
Multiply through by 4
4y = 3x + 12 or
3x + 12 = 4y ( subtract 12 from both sides )
3x = 4y - 12 ( subtract 4y from both sides )
3x - 4y = - 12 ← in standard form