According to the question,
The Kinetic Energy will be:
= [tex]\frac{1}{2}mv^2[/tex]
By putting the values,
= [tex]\frac{1}{2}\times 62\times (0.8)^2[/tex]
= [tex]31\times 0.64[/tex]
= [tex]20 \ Nm[/tex]
Thus the above answer is right.
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