Respuesta :

Answer:

Step-by-step explanation:

Given the function [tex]g(x,y) = x^{4}y+3siny+5ycosx[/tex]

before we can get its second order partial derivative, we need to get its first order first. The first order are δg/δx and δg/δy

δg/δx  [tex]= 4x^{3}y - 5ysinx[/tex]

δg/δy = [tex]x^{4} +3cosy+5cosx[/tex]

The second derivatives are δ²g/δy²,  δ²g/δx², δ²g/ δyδx or δ²g/ δxδy

δ²g/δy² =  δ/δy (δg/δy) = δ/δy([tex]x^{4}+3cosy+5cosx[/tex])  

δ²g/δy² = -3siny

Similarly δ²g/δx² =  δ/δx (δg/δx) = δ/δx([tex]4x^{3}y - 5ysinx[/tex])

δ²g/δx² = 12x²y-5ycosx

δ²g/ δyδx =   δ/δy (δg/δx) =   δ/δy ([tex]4x^{3}y - 5ysinx[/tex])

δ²g/ δyδx  = 4x³ - 5sinx = δ²g/ δxδy ( for continuous function)

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