Answer:
Step-by-step explanation:
Given the function [tex]g(x,y) = x^{4}y+3siny+5ycosx[/tex]
before we can get its second order partial derivative, we need to get its first order first. The first order are δg/δx and δg/δy
δg/δx [tex]= 4x^{3}y - 5ysinx[/tex]
δg/δy = [tex]x^{4} +3cosy+5cosx[/tex]
The second derivatives are δ²g/δy², δ²g/δx², δ²g/ δyδx or δ²g/ δxδy
δ²g/δy² = δ/δy (δg/δy) = δ/δy([tex]x^{4}+3cosy+5cosx[/tex])
δ²g/δy² = -3siny
Similarly δ²g/δx² = δ/δx (δg/δx) = δ/δx([tex]4x^{3}y - 5ysinx[/tex])
δ²g/δx² = 12x²y-5ycosx
δ²g/ δyδx = δ/δy (δg/δx) = δ/δy ([tex]4x^{3}y - 5ysinx[/tex])
δ²g/ δyδx = 4x³ - 5sinx = δ²g/ δxδy ( for continuous function)