answer:
Total surface area of 3 tanks=34.3 m^2
7 tins of paint are required.
Solution,
diameter of tank=1.4 m
Height of tank=1.9 m
Given tank has top and bottom
Now, The total surface area of cylinder tank is given by:
[tex]tsa = 2\pi \: {r}^{2} + (2\pi \: r \: ) \times h[/tex]
r( radius of tank)=
[tex] \frac{diameter}{2} = \frac{1.4}{2} = 0.7 \: m[/tex]
h(height of tank)=1.9 m
TSA of 1 tank
=
[tex]2 \times 3.14 \times {(0.7)}^{2} + 2 \times 3.14 \times 0.7 \times 1.9 \\ = 11.435 \: {m}^{2} [/tex]
TSA Of 3 tanks
=
[tex]3 \times 11.435 \: {m}^{2} \\ = 34.3 \: {m}^{2} [/tex]
Given a tin of plate covers 5m^2 area.
No.of tins required:
1 tin 5m^2
x tin 34.3 m^2
[tex]5x = 34.3(cross \: multiplication) \\ or \: x = \frac{34.3}{5} \\ x = 6.86 \\ x = 7 \: tins[/tex]
therefore 7 tins are required.
Hope this helps...
Good luck on your assignment....
