Question

Please help. thanks so much for the effort

Answer 1

Answer:

The gradient of the curve at point x = 2 is 5.

Step-by-step explanation:

Given that 1st derivative of equation y is gradient. So you have to differentiate first :

$y = 2 {x}^{2} - 3x$

$\frac{dy}{dx} = 2(2)x - 3$

$\frac{dy}{dx} = 4x - 3$

Next, you have to put in the value of x :

$let \: x = 2$

$\frac{dy}{dx} = 4(2) - 3$

$\frac{dy}{ dx} = 8 - 3$

$\frac{dy}{dx} = 5$

$gradient = 5$