Question

What change occurs to the gravitational force of attraction between two bodies when the
distance between them is made half (1/2) by keeping masses constant?​

Answer 1

Answer:

when the radius is halved, F becomes 4 times

Explanation:

The formula is given by

$F = \frac{Gm1m2}{r^2}$

When r is halved:

$F = \frac{Gm1m2}{(1/2r)^2}$

=> $F = \frac{Gm1m2}{1/4 r^2}$

=> $F = 4(\frac{Gm1m2}{r^2} )$

This means when the radius is halved, F becomes 4 times