Answer:
30
Step-by-step explanation:
Using the definition
n[tex]P_{r}[/tex] = [tex]\frac{n!}{(n-r)!}[/tex]
where n ! = n(n - 1)(n - 2)(n - 3)... × 3 × 2 × 1
Thus
6[tex]P_{2}[/tex] = [tex]\frac{6!}{4!}[/tex] = [tex]\frac{6.5.4.3.2.1}{4.3.2.1}[/tex] ← cancel 4.3.2.1 on numerator/ denominator, leaving
= 6 × 5
= 30
