What is the equation of the line, in slope-intercept form, that passes through (3,-1) and (-1, 5)?
2 x + 3 y - 7 = 0
2 y=-3x+7
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Respuesta :

Answer:

[tex]2y = -3x+7[/tex]

Step-by-step explanation:

The coordinates are (3,-1) and (-1,5)

Finding the slope :

Slope = [tex]\frac{rise}{run}[/tex]

Slope = [tex]\frac{5+1}{-1-3}[/tex]

Slope = [tex]\frac{6}{-4}[/tex]

Slope = [tex]-\frac{3}{2}[/tex]

Now Finding y-intercept.

For this, we'll take any point

Let it be (3,-1)

So,

Point = (x,y) = (3,-1)

=> x = 3, y = -1

Putting in slope intercept form to get b

=> [tex]y = mx+b[/tex]

=> -1 = (3)([tex]-\frac{3}{2}[/tex]) + b

=> b =  -1 +  [tex]\frac{9}{2}[/tex]

=> b = [tex]\frac{7}{2}[/tex]

Putting m and b in the slope intercept form to get the required equation of line

=> [tex]y = mx+b[/tex]

=> [tex]y = \frac{-3x+7}{2}[/tex]

=> [tex]2y = -3x+7[/tex]

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