Respuesta :
Answer:
The expression which is equivalent to (6c² + 3c)/(-4c + 2) ÷ (2c + 1)/(4c - 2) is -3c.
Step-by-step explanation:
The given fraction is:
(6c² + 3c)/(-4c + 2) ÷ (2c + 1)/(4c - 2)
Simplify the equation:
3c(2c+1) / -2(2c - 1) ÷ (2c +1)/2(2c-1)
Change the division sign into a multiplication sign
3c(2c+1) / -2(2c - 1) × 2(2c-1)/(2c+1)
Cancelling 2(2c-1) :
3c(2c+1)/ -1 × 1/(2c+1)
Cancelling 2c+1 :
3c/-1 × 1/1
Simplifying:
-3c
Hench the given fraction is equals to -3c.
The expression equivalent the given expression is [tex]-3c[/tex].
Given expression is,
[tex]=\frac{6c^{2}+3c }{-4c+2}\div \frac{2c+1}{4c-2} \\\\=\frac{3c(2c+1)}{-4c+2}*\frac{-(-4c+2)}{2c+1}[/tex]
Here we observed that (2c + 1) and (-4c + 2) are cancelled out to each other from numerator and denominator.
[tex]=\frac{3c(2c+1)}{-4c+2}*\frac{-(-4c+2)}{2c+1}\\\\=-3c[/tex]
Hence, The expression equivalent the given expression is [tex]-3c[/tex].
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