Find a 92.9% confidence interval for the difference p1−p2p1−p2 of the population proportions.
Hint: For a level of confidence (1−α)⋅100%(1−α)⋅100%, z∗z∗ is the value that leaves an area of (1−α)/2(1−α)/2 to its right in a standard normal distribution
I hope that helps
