Question

Suppose that we want to prepare 1 L of a 0.400 M HCL solution from a solution of 1.00 M HCL

Answer 1

Answer:

Use 0.400 L of the 1.00 mol·L⁻¹ solution.  

Explanation:

We can use the dilution formula to calculate the volume needed.

V₁c₁ = V₂c₂

Data:

V₁ = 1 L; c₁ = 0.400 mol·L⁻¹;  

V₂ = ?;  c₂ =   1.00   mol·L⁻¹;  

Calculation:

$\begin{array}{rcl}V_{1}c_{1} & = & V_{2}c_{2}\\\text{1 L}\times \text{0.400 mol/L} & = & V_{2} \times\text{1.00 mol/L}\\\text{0.400 L} & = & 1.00V_{2}\\V_{2}&=& \text{0.400 L}\\\end{array}\\\text{You need \large \boxed{\textbf{0.400 L}} of the 1.00 mol/L solution.}$