Lim x-> n/2 (2e^x cos x)

Answer:
A
Step-by-Step Explanation:
We want to find the limit:
[tex]\displaystyle{\lim_{x\to\frac{\pi}{2}}(2e^x\cos(x))}[/tex]
Use direct substitution.
Hence:
[tex]\displaystyle{\Rightarrow 2e^\frac{\pi}{2}\cos(\frac{\pi}{2}})[/tex]
Recall the unit circle. cos(π/2) is simply 0. Hence:
[tex]\displaystyle{\Rightarrow 2e^\frac{\pi}{2}(0)=0[/tex]
Therefore:
[tex]\displaystyle{\lim_{x\to\frac{\pi}{2}}(2e^x\cos(x))}=0[/tex]
So, our answer is A.