Answer:
[tex]\displaystyle y=-\frac{5}{2}x+13[/tex]
Step-by-Step Explanation:
We want to find the equation of the line in slope-intercept form that passes through the point (6, -2) and has a slope of -5/2.
We can use the point-slope form:
[tex]y-y_1=m(x-x_1)[/tex]
Where m is our slope and (x₁, y₁) is a point.
So, we will substitute -5/2 for m and (6, -2) for (x₁, y₁). Hence:
[tex]\displaystyle y-(-2)=-\frac{5}{2}(x-6)[/tex]
Distribute:
[tex]\displaystyle y+2=-\frac{5}{2}x+15[/tex]
Finally, subtract 2 from both sides. Hence, our equation is:
[tex]\displaystyle y=-\frac{5}{2}x+13[/tex]
