Answer:
9/32 inch diameter pin will not fit into a reamed hole with a diameter of 0.278 inch
Step-by-step explanation:
Diameter of reamed hole = 0.278 inch
Radius of reamed hole = [tex]\frac{0.278}{2} =0.139[/tex]
Surface area of reamed hole = [tex]\pi r^2[/tex]
Surface area of reamed hole = [tex]3.14 \times (0.139)^2[/tex]
Surface area of reamed hole = 0.06066794
Diameter of pin = [tex]\frac{9}{32}[/tex]
Radius of pin =[tex]\frac{9}{64}[/tex]
Surface area of pin = [tex]\pi r^2 = 3.14 \times ( \frac{9}{64})^2=0.0620[/tex]
Since the surface area of pin is more than the surface area of hole .
So, a 9/32 inch diameter pin will not fit into a reamed hole with a diameter of 0.278 inch