Answer: 391 g
Explanation:
For this problem, we need to know that molarity is. Molarity is moles of solute/liters of solution. it is also denoted as M=n/V, which is also mol/L. We are given that the molarity is 3.0 M and the liter is 1.5 L. All we have to do is plug in 3.0 and 1.5 into our formula and solve for moles.
[tex]3.0M=\frac{n}{1.5L}[/tex]
[tex]n=4.5 mols[/tex]
Now that we have moles, we can convert moles to grms by using the molar mass of LiBr.
[tex]4.5 mols*\frac{86.844 g}{1 mol} =391g[/tex]
