Question

1

What is the point-slope form of a line that has a slope of -4 and passes through point (-3, 1)?
=
oy-(-3) --4(x-1)
y-1--4[*-(-3))
-1-y, = -44-3-X)
3-y,--4(1-x) ​

Answer 1

Answer:

$-4(x+3) = y - 1$

Step-by-step explanation:

Given

Slope of line = -4

Point = (-3,1)

Required

Point slope equation of line

To get the equation of line, we make use of the following slope formula

$m = \frac{y - y_1}{x - x_1}$

Where m = -4 and $(x_1,y_1) = (-3,1)$

So; $m = \frac{y - y_1}{x - x_1}$ becomes

$-4 = \frac{y - 1}{x - (-3)}$

$-4 = \frac{y - 1}{x +3}$

Multiply both sides by x + 3

$-4(x+3) = \frac{y - 1}{x +3} * (x+3)$

$-4(x+3) = y - 1$

Hence, the point slope form of the line is $-4(x+3) = y - 1$