The coordinates of rhombus ABCD are A(–4, –2), B(–2, 6), C(6, 8), and D(4, 0). What is the area of the rhombus? Round to the nearest whole number, if necessary. 30 square units 60 square units 102 square units 120 square units

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Answer:

Brainleist!!!!

Step-by-step explanation:

First calculate the distance between B and D, A and C. 

We have the distance between B and D will be:  sqrt[(x2-x1)^2+(y2-y1)^2] = 8.5

The distance between A and C will be: 14.14 

We have the area of rhombus: 1/2 * 8.5 * 14.14 = 60 square units. 

The area of the rhombus to the nearest whole number is 60 square units

How to calculate the area of a rhombus

To do that we have to calculate the length of BD is expressed as:

Calculate the length of BD;

BD = [tex]\sqrt{(x^2-x^1)^2+(y^2-y^1)^2}\\[/tex]

Substiuting the given coordinate point, the distance of AB is 8.5 units

Similarly, the distance between A and C will be: 14.14  units

Area of rhombus: 1/2 * 8.5 * 14.14 = 60 square units

Hence the area of the rhombus to the nearest whole number is 60 square units

Learn more on area of rhombus here; https://brainly.com/question/311403

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