Answer:
x^2+2x+2
Step-by-step explanation:
If the roots of the equation are -1\pm i, then by the zero product rule:
[tex]x=-1\pm i \\\\x+1\pm i=0 \\\\(x+1+i)(x+1-i)=0\\\\x^2+x-ix+x+1-i+ix+i+1=0 \\\\x^2+2x+2=0[/tex]
You can confirm this with the quadratic equation:
[tex]x=\dfrac{-2\pm\sqrt{4-8}}{2}=\dfrac{-2\pm 4i}{2}=-1\pm i[/tex]
Hope this helps!