Question

Determine the slope-intercept form of the equation of the line parallel to y = x + 11 that passes through the point (–6, 2). y = x +

Answer 1

Answer:

$y = x+12$

Step-by-step explanation:

Parallel => This means it has the same slope as this one.

Slope = m = 1

Now,

Point = (x,y) = (-6,2)

So, x = -6, y = 2

Putting this in slope intercept form to get b

$y = mx+b$

=> 2 = (1)(-6) + b

=> b = 2+6

=> b = 8

Now putting m and b in the slope-intercept form to get the required equation:

=> $y = mx+b$

=> $y = x+12$

Answer 2

Answer:

Now, I’m gonna assume that the equation is actually y = -4/3x + 11

The answer would be -4/3x - 6

Step-by-step explanation:

So since the line is parallel to the equation, y = -4/3x + 11, that means they have the same slope, so it’s -4/3x.

Using point-slope form, we can create an equation.

y - 2 = -4/3 (x + 6)

y1 = 2 and x1 = -6, we made it into +6 because subtracting a negative makes it addition.

Now our final equation would be y = -4/3x - 6