Respuesta :
Answer:
$3448.81
Step-by-step explanation:
Using the compound interest formula to calculate the amount compounded after 10years.
[tex]A = P(1+r)^{nt}[/tex]
P = principal = $2000
r = rate (in %) = 5.6%
t = time (in years) = 10years
n = 1year = time used in compounding
[tex]A = 2000(1+0.056)^{10} \\A = 2000(1.056)^{10}\\A = 2000*1.7244046\\A = 3448.81 (to\ 2dp)[/tex]
Amount compounded after 10 years is $3448.81
The number of years it would take the investment to double is 12.38 years.
The amount after 10 years is $21,151.95.
The formula used to determine the future value of an investment when interest is compounded continuously is:
FV = A x [tex]e^{r}[/tex] x N
- A= amount invested = $2000
- e = 2.7182818
- N = number of years
- r = interest rate = 5.6%
- FV = future value
Time to double :
FV = $4000
FV / PV = 2
n = log(2) ÷ log(e) ÷ 0.056 = 12.38 years
Amount after 10 years
$2000 x [tex]e^{r}[/tex] x 10 = $21,151.95
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