Can someone help me with the below question???

Answer:
so 2a+3b=±13
Step-by-step explanation:
4a²+9b²=97
ab=6
2a+3b=?
by using formula
(a+b)²=a²+b²+2ab
(2a+3b)²=(2a)²+(3b)²+2(2a)(3b)
(2a+3b)²=4a²+9b²+12ab
putting values
(2a+3b)²=97+12(6)
(2a+3b)²=97+72
(2a+3b)²=169
taking square root on both sides
√(2a+3b)²=√169
2a+3b=±13
i hope it will help you
Answer:
2a+3b = 13
Step-by-step explanation:
Using this formula
[tex](x+y)^2 = x^2+y^2+2xy[/tex]
Where,
x = 2a and y = 3b
Putting in the above formula
=> [tex](2a+3b)^2=4a^2+9b^2+12ab[/tex]
Putting 4a²+9b² = 97 and ab = 6
=> (2a+3b)² = 97+12(6)
=> (2a+3b)² = 97+72
=> (2a+3b)² = 169
Taking sqrt on both sides
=> 2a+3b = 13