Answer:
Step-by-step explanation:
Using the compound interest formula
[tex]A = P(1+\frac{r}{n} )^{nt}[/tex]
A = final amount after t years
P = amount borrowed = Principal = 6709R
r = rate (in %) = 12 1/3%
n = number of times the interest is applied = 2 months
t = time the period elapsed = 2 1/2 years
[tex]A = 6709(1+\frac{\frac{37}{300} }{\frac{2}{12} } )^{\frac{2}{12} *\frac{5}{2} } \\A = 6709(1+0.1233/0.1667)^{2\0.41667} \\A = 6709(1+0.7397)^{2\0.41667} \\A = 6709(1.7397)^{2\0.41667} \\A = 6709(3.81195)\\A = 25,574.373[/tex]
She will have to pay 25,574.373R after 2 and a half years
interest paid by her = Amount - Principal
Interest paid by her = 25,574.373 - 6709
Interest paid by her = 18,865.373R