Question

write a phythagoras triplet whose one is no. 17​

Answer 1

8, 15, 17

$2m, \: m^2-1, \: m^2+1$

17 can be expressed as $16+1 = 4^2+1$

$m=4$

$2(4), \: (4)^2-1, \: (4)^2+1$

$8, 16-1, 16+1$

$8,15,17$