Question

60 drops fell from a burret.The first and final readings were 28cm³ and 43cm³ respectively.what is the average volume of one drop​

Answer 1

Answer:

$0.25\ cm^3$

Explanation:

Data provided in the question

Number of drops fell from a burret = 60

The first reading is 28 cm^3

And, the final reading is 43 cm^3

Based on the above information, the average volume of one drop is

$= \frac{Final\ readings - first\ readings}{number\ of\ drops}$

$= \frac{43\ cm^3 - 28\ cm^3}{60 \ drops}$

$= 0.25\ cm^3$

Basically we applies the above formula by applying the three items given in the question so that the average volume of one drop could come

Answer 2

Answer:

0.25\ cm^30.25 cm

3

Explanation:

Data provided in the question

Number of drops fell from a burret = 60

The first reading is 28 cm^3

And, the final reading is 43 cm^3

Based on the above information, the average volume of one drop is

= \frac{Final\ readings - first\ readings}{number\ of\ drops}=

number of drops

Final readings−first readings

= \frac{43\ cm^3 - 28\ cm^3}{60 \ drops}=

60 drops

43 cm

3

−28 cm

3

= 0.25\ cm^3=0.25 cm

3