Answer:
( About ) 2.42 pH
Explanation:
First convert grams to mole of the hydrochloric acid,
HCl ( moles ) = 0.7g * ( 1 mole / 36.5g ),
0.7 / 36.5 = ( About ) 0.0192 moles
Now take the moles as a fraction over the given liters, to determine " M, " the apparent pH
M = 0.0192 mole / 5.0 L,
M = 0.00384M
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Because HCl is a strong acid and will completely ionized, take a look at the steps below,
[ H+ ] = 0.00384M pH = -log[H+] = - log[0.00384],
- log[0.00384] = - ( - 2.41566... )
Solution = ( About ) 2.42 pH