Question

Will mark brainliest! Would also really appreciate it if someone could explain it as well!
$2 sin^{2} (x) \geq sin(x)$

Answer 1

Answer:

sin (x) ≥ 0, between 0° and 180° or 0 and π,

sin(x) ≥ 1/2, between 30° and 150° or π/6 and 5π/6

Step-by-step explanation:

This is how I would do it. Subtract sin(x) from both sides

2$sin^{2} (x)$ - sin(x) ≥ 0 , then factor out sin(x)

sin(x) [2 sin(x) - 1] ≥0, then set each factor ≥ 0

sin(x) ≥ 0 and 2 sin(x) - 1 ≥ 0

sin (x) ≥ 0, between 0° and 180° or 0 and π

2 sin(x) ≥ 1

sin(x) ≥ 1/2, between 30° and 150° or π/6 and 5π/6