Answer:
Acceleration is 8.45 and the tension is 2.775
Explanation:
Lets apply the equation F=ma for vertical block,
5-T= 0.5a
foe the frictional force acting on the object,
f=0.11×5 (consider equation no.1)
=0.55N
Applying F=ma for the block which is on surface,
T-0.55=0.5a (consider as equation no.2)
no.1=no.2
5.55=2T
T=2.775
by equation no.1,
4.225=0.5a
a=8.45
