Question

A population of 100 frogs increases at an annual rate of 22%. How many frogs will there be in 5 years? Exponential growth or decay?: Write a function that represents the situation: - Initial amount: -Growth/Decay rate: -Answer:

Answer 1

Answer: 270 frogs

Step-by-step explanation:

Initial amount = 100

Growth / Decay rate = 122% = 1.22

y = 100 (1.22)^5

y = 100 x 2.70271

y = 270.271

Answer 2

Answer:

Exponential growth

a = 100 initial value

b = 1.22

y = 100 ( 1.22) ^x

in 5 years= 270 frogs

Step-by-step explanation:

Exponential growth is in the form

y = ab^x  where a is the initial value and b is the growth rate

a = 100

b = 1+ 22% = 1.22

y = 100 ( 1.22) ^x

Let x = 5 years

y = 100 ( 1.22)^5

 =270.2708 frogs

Rounded to the nearest frog

270 frogs