A line passes through the points (–6, 4) and (–2, 2). Which is the equation of the line? y = negative one-half x + 1 y = one-half x + 7 y = –2x – 8 y = 2x + 16

Respuesta :

Answer:

y = - [tex]\frac{1}{2}[/tex] x + 1

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (- 6, 4) and (x₂, y₂ ) = (- 2, 2)

m = [tex]\frac{2-4}{-2+6}[/tex] = [tex]\frac{-2}{4}[/tex] = - [tex]\frac{1}{2}[/tex] , thus

y = - [tex]\frac{1}{2}[/tex] x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (- 2, 2), then

2 = 1 + c ⇒ c = 2 - 1 = 1

y = - [tex]\frac{1}{2}[/tex] x + 1 ← equation of line

Answer:

A

Step-by-step explanation:

got it on edge

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