Question

1/$\sqrt{9} - \sqrt{8}$ is equal to:

(A) 1/2(3-2$\sqrt{2}$)
(B) 1/(3+2$\sqrt{2}$)
(C) 3-2$\sqrt{2\\}$
(D) 3+2$\sqrt{2}$

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Answer 1

Answer:

D)

Step-by-step explanation:

=> $\frac{1}{\sqrt{9}-\sqrt{8} }$

Multiplying and dividing by conjugate $\sqrt{9} +\sqrt{8}$

=> $\frac{1}{\sqrt{9}-\sqrt{8} }* \frac{\sqrt{9}+\sqrt{8} }{\sqrt{9}+\sqrt{8}}$

=> $\frac{\sqrt{9}+\sqrt{8} }{\sqrt{9^2-\sqrt{8}^2 } }$

=> $\frac{\sqrt{9} +\sqrt{8}}{9-8}$

=> $\sqrt{9} +\sqrt{8}$

=> 3 + $2\sqrt{2}$