Answer:
For this case we can set a proportion rule like this:
[tex] \frac{8.1}{100-22.3} = \frac{x}{100}[/tex]
where x is the interest rate 10 years ago and if we solve for x we got:
[tex] x = 100 *\frac{8.1}{77.7}= 10.42%[/tex]
So then the interest rate 10 years ago is about 10.42 %
Step-by-step explanation:
For this case we can set a proportion rule like this:
[tex] \frac{8.1}{100-22.3} = \frac{x}{100}[/tex]
where x is the interest rate 10 years ago and if we solve for x we got:
[tex] x = 100 *\frac{8.1}{77.7}= 10.42%[/tex]
So then the interest rate 10 years ago is about 10.42 %