Complete question:
A fish story: The mean length of one-year-old spotted flounder, in millimeters, is 126 with standard deviation of 23, and the mean length of two-year-old spotted flounder is 161 with a standard deviation of 27. The distribution of flounder lengths is approximately bell-shaped.
Anna caught a one-year-old flounder that was 145 millimeters in length. What is the z-score for this length? Round the answers to at least two decimal places. Anna's z-score is
Answer:
0.83
Step-by-step explanation:
Given:
For one year old:
Mean, u = 126
Standard deviation, [tex] \sigma[/tex] = 23
For two year old:
Mean, u = 161
Standard deviation, [tex] \sigma[/tex] = 27
Anna caught a one year old with length of 145. Ie, X = 145
Required: Find the Z score.
Take the Z score formula:
[tex] Z = \frac{X - u}{\sigma} [/tex]
Substitute figures:
[tex] Z = \frac{145 - 126}{23}[/tex]
[tex] Z = \frac{19}{23} [/tex]
[tex] = 0.826 [/tex]
Approximately 0.823
Z score = 0.83