Question

In right triangle ABC, ∠A is a right angle and sinC=35. What is the ratio for tanC? Enter your answer as the fraction, in simplest terms, like this: 42/53 (Look at the attached image)

Answer 1

Answer:

tan(C) = 3/4

Step-by-step explanation:

If the sine of angle C is 3/5 and we want to find the tangent of the angle C, we can first find the cosine of angle C using the following equation:

$sin^2(C) + cos^2(C) = 1$

$(3/5)^2 + cos^2(C) = 1$

$cos^2(C) = 1 - 9/25$

$cos^2(C) = 16/25$

$cos(C) = 4/5$

Then, we can find the tangent relation using the equation:

$tan(C) = sin(C) / cos(C)$

$tan(C) = (3/5) / (4/5)$

$tan(C) = 3/4$