Question

. What is P(3, then 3) when spinning the spinner shown at the right twice? A. 14 B.116 C. 156 D. 164

Answer 1

Question Correction

The spinner shown is divided into 8 equal sections labeled 0 to 7. What is P(3, then 3) when spinning the spinner shown at the right twice?

A. 1/4 B.1/16 C. 1/56 D. 1/64

Answer:

$(D)\dfrac{1}{64}$

Step-by-step explanation:

Number of Sections on the Spinner =8

Probability of Spinning a 3, $P(3)=\dfrac{1}{8}$

Therefore:

$P(3, then 3)=\dfrac{1}{8} \times \dfrac{1}{8}\\=\boxed{\dfrac{1}{64}}$

The correct option is D.

Remark:  In option C, we have $\dfrac{1}{8} \times \dfrac{1}{7}=\dfrac{1}{56}$ , however, the outcome of the first spin does not affect the outcome of the second spin, therefore this option is wrong.