Answer:
The energy required is same for both cases since specific heat capacity (Cp) does not vary with pressure.
Explanation:
Given;
initial temperature, t₁ = 50 °C
final temperature, t₂ = 80 °C
Change in temperature, ΔT =80 °C - 50 °C = 30 °C
Pressure for case 1 = 1 atm
Pressure for case 2 = 3 atm
Energy required in both cases is given;
[tex]Q = M*C_p*\delta T[/tex]
where;
Cp is specific heat capacity, which varies only with temperature and not with pressure.
Therefore, the energy required is same for both cases since specific heat capacity (Cp) does not vary with pressure.