Homework help, one of the few I have

Answer:
x=11 solution is not extraneous
Step-by-step explanation:
sqrt( x-5) +7 = 11
Subtract 7 from each side
sqrt( x-5) +7-7 = 11-7
sqrt(x-5) = 4
Square each side
(sqrt(x-5))^2 = 4^2
x-5 = 16
Add 5 to each side
x-5+5 = 16+5
x = 21
Check
sqrt( 21-5) +7 = 11
sqrt(16) +7 =11
4+7 =11
11=11
Valid solution
Answer:
B) x = 21, solution is not extraneous
Step-by-step explanation:
√(x - 5) + 7 = 11
(√(x - 5) + 7) - 7 = 11 - 7
√(x - 5) = 4
(√(x - 5))² = (4)²
x - 5 = 16
(x - 5) + 5 = 16 + 5
x = 21
The solution is not extraneous. An extraneous solution is a solution that is not included in the domain. For this equation the domain would be [-5, ∞). The solution found is included in the domain