Answer:
Magnification is 1.8
Explanation:
Given data
object distance u = 24.8 cm
focal length f= 16 cm
image distance v= ?
In other to solve for the magnification we have to solve for the image distance
The mirror formula is
[tex]\frac{1}{v} +\frac{1}{u}= \frac{1}{f} \\[/tex]
Substituting we have
[tex]\frac{1}{v} +\frac{1}{24.8}= \frac{1}{16} \\\\\frac{1}{v}= \frac{1}{16} -\frac{1}{24.8}\\\\\frac{1}{v}=\frac{24.8-16}{396.8}= \frac{8.8}{396.8}= \frac{1}{45}\\\\v= 45cm[/tex]
The magnification is
[tex]m= \frac{v}{u}\\\m= \frac{45}{24.8}\\\\m= 1.8[/tex]
