Question

Consider the following reversible reaction. CO(g)+2H2(g) CH3OH(g) What is the equilibrium constant expression for the given system?

Answer 1

B - Keq = [CH3OH]/[CO][H2]2

Answer 2

Kc=28.7  is the equilibrium constant

How is the equilibrium constant 28.7 explain?

[CO]=26.7g(28.01g/mol)(5.25L)=0.182M

[H2]=2.33g(2.016g/mol)(5.25L)=0.220M

[CH3OH]=8.65g(32.04g/mol)(5.25L)=0.0514M

Kc= x/(0.182−x)(0.220−2x)2

   = 0.0514/(0.182−0.0514)(0.220−2(0.0514))2

   = 28.7

What is equilibrium constant?

a number that expresses the relationship between the amounts of products and reactants present at equilibrium in a reversible chemical reaction at a given temperature.

So, this shows the equilibirum constant is 28.7

learn more about equilibirum constant here;

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