What is the value of x in the equation (StartFraction one-half EndFractionx + 12) = StartFraction one-half EndFraction(StartFraction 2 Over 3 EndFraction left-parenthesis StartFraction one-half EndFraction. x plus 12 right-parenthesis equals left-parenthesis StartFraction one-half EndFraction left-parenthesis StartFraction one-third EndFraction x plus 14 right-parenthesis minus 3.x + 14) – 3?

–24
–6
negative StartFraction 2 Over 3 EndFraction.
0

Respuesta :

Answer:

[tex]x = -24[/tex]

Step-by-step explanation:

Your question is not well presented

Given

[tex]\frac{2}{3}(\frac{1}{2}x + 12) = \frac{1}{2}(\frac{1}{3}x + 14) - 3[/tex]

Required

Solve for x

[tex]\frac{2}{3}(\frac{1}{2}x + 12) = \frac{1}{2}(\frac{1}{3}x + 14) - 3[/tex]

Open Brackets

[tex]\frac{2}{3}*\frac{1}{2}x + \frac{2}{3}*12 = \frac{1}{2}*\frac{1}{3}x +\frac{1}{2}* 14 - 3[/tex]

[tex]\frac{1}{3}x + \frac{2*12}{3} = \frac{1}{6}x +\frac{14}{2} - 3[/tex]

[tex]\frac{1}{3}x + \frac{24}{3} = \frac{1}{6}x +\frac{14}{2} - 3[/tex]

[tex]\frac{1}{3}x + 8 = \frac{1}{6}x +7 - 3[/tex]

Collect Like Terms

[tex]\frac{1}{3}x - \frac{1}{6}x= 7 - 3 - 8[/tex]

[tex]\frac{1}{3}x - \frac{1}{6}x= -4[/tex]

Take LCM

[tex]\frac{2-1}{6}x= -4[/tex]

[tex]\frac{1}{6}x= -4[/tex]

Multiply both sides by 6

[tex]6*\frac{1}{6}x= -4*6[/tex]

[tex]x= -4*6[/tex]

[tex]x = -24[/tex]

Answer: option A.  -24

Step-by-step explanation:

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