Question

If a line has a slope of 3 and contains the point (-1, 4), what is its equation in
point-slope form?
A. y + 1 = 3(x-4)
B. y - 4 = 3(x - 1)
C. y - 1 = 3(x-4)
D. y - 4 = 3(x + 1)

Answer 1

Answer:

The equation in point slope form would be D

Step-by-step explanation:

The equation in letters would be y-$y_{1}$=m(x-$x_{1}$). You plug it in and you will get the answer.

Answer 2

The equation of the line in point-slope form with a slope of 3 and contains the point (-1, 4) is y - 4 = 3(x + 1). So, option D. is the correct option.

What is the point-slope form of a linear equation?

A relation between x and y, which when plotted on a coordinate plane, gives a straight line is a linear equation.

The equation of a line with a slope m and passing through the points (x₁, y₁) is given by:

y - y₁ = m(x - x₁).

This form is the point-slope form of a linear equation.

How do we solve the given question?

We are informed that the line has a slope of 3 and contains the point

(-1, 4). Going by the point-slope form, we have m = 3, x₁ = -1, and y₁ = 4.

Substituting these values in the equation, we get

y - 4 = 3(x - (-1))

or, y - 4 = 3(x + 1), which is option D.

∴ The equation of the line in point-slope form is y - 4 = 3(x + 1).

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