What is the permeter of square ABCD?

Answer:
24.3 units (3 s.f.)
Step-by-step explanation:
Since a square has 4 equal sides,
perimeter of ABCD= 4(length of AB)
Distance between 2 points
=[tex] \sqrt{(y1 - y2)^{2} + (x1 - x2)^{2} } [/tex]
Length of AB
[tex] = \sqrt{( { - 2 - 4)}^{2} + {(2 - 3)}^{2} } \\ = \sqrt{( - 6)^{2} + ( - 1)^{2} } \\ = \sqrt{37} [/tex]
perimeter of ABCD
[tex] = 4 \sqrt{37} \\ = 24.3 \: units \: (3 \: s.f.)[/tex]