Answer:
Explanation:
Given the following parameters;
Tension in the wire T = 821N
wave speed of the transverse wave v = 185m/s
density of nickel = 8.9*10³kg/m³
radius of the wire = ?
Using the relationship for finding the speed of the wave to first get the linear density;
[tex]v = \sqrt{\frac{T}{\mu} }[/tex] where [tex]\mu[/tex] is the linear density
[tex]185 = \sqrt{\frac{821}{\mu} }\\185^{2} = \frac{821}{\mu} \\\mu = \frac{821}{185^{2} }\\\mu = 0.024kg/m[/tex]
Also;
[tex]\mu[/tex] = mass m/Length L
Since mass m = density [tex]\rho[/tex] * volume [tex]V[/tex]
[tex]\mu = \frac{\rho V}{L}[/tex]
[tex]\mu = \frac{\rho AL}{L}\\\mu = \rho A[/tex]
Since A = area of the wire = [tex]\pi r^{2}[/tex]
[tex]\mu = \rho \pi r^{2}[/tex]
Given [tex]\mu = 0.024kg/m \ and\ \rho = 8.9*10^{3}kg/m^{3}[/tex]
0.024 = 8.9*10³*3.14r²
0.024 = 27.946r²
r² = 0.024/27.964
r² = 8.6*10^-7
r =√8.6*10^-7
r = 9.27*10^-4m
Radius of the wire is 9.27*10^-4m